Question

The distance between a proton and an electron
both having a charge 1.6 x 10-19 coulomb of a
hydrogen atom is 10-10
metre. The value of
intensity of electric field produced on the
electron due to proton will be
(A) 2.304 x
10-10 N/C
(B) 14.4 V/m
(C) 16 V/m
(D) 1.44 x 10' N/C​

Answer 1

Answer:

D

Explanation:

charge of e- =1.6×10^-19

ratio=10^-10

E=9×10^9×1.6×10^-19/(10^-10)^2

= 1.44 ×10^11 newton/COLAM

Answer 2

Explanation:

1.44×10¹¹ N/C is the value of intensity of electric field produced on electron due to proton