Question

the distance between points A (4, k )and B (7,6 )is 5 units then find the value of k​

Answer 1

I hope you got to know

Answer 2

AB=√[( 7-4)^2+(6-k)^2]

5^2= 3^2+36+k^2-12k

25=9+36+k^2-12k

25-45=k2-12k

k2-12k=-20

k2-12k+20=0

k2-2k-10k+20=0

k(k-2)-10(k-2)=0

(k-2) (k-10)=0

so, k=2 and k= 10.

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