the distance between points A (x,3) and B (5 ,7) is 5 units find the value of x
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Step-by-step explanation:
A ( x,3) And B (5,7) Be the two points
Form the Above points we get
X1 = x
X2 = 5
Y1 = 3
Y2 = 7
Also given
distance between A and B = 5 units
We know that Distance between two points= √ (x2- x1)²+(y2-y1)²
Now substitute the values
√ (x2- x1)²+(y2-y1)² = 5
√ (5-x)²+(7-3)² = 5
squaring on both sides
(5-x)²+ 16 = 25
(5-x)² = 25-16
(5-x)². = 9
5-x. = ±√ 9
5-x. =± 3
Case i
5-x. = 3
5-3. = x
x= 2
Case ii
5-x = -3
5+3= x
x = 8
Therefore the values of X are = 2,8
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