Question

The distance between pts P(-1, 1) and
Q (5,-7) is ..?​

Answer 1

Answer:

√-10

Step-by-step explanation:

formula is √(x2-x1)^2+(y2-y1)^2

here X2=1,x1=-1,y1=5,y2=-7

now

√(1-(-1))+(-7-5)

=√2-12

=√-10

please mark me as Brainliest Answer

Answer 2

Answer:

distance=√(x2-x1)²+(y2-y1)²

=√(5+1)²+(-7-1)²

=√6²+(-8)²

=√36+64

=√100

=10

so the distance between P and Q is =10 u. ans.

Step-by-step explanation: