The distance between sun and earth is 1.496 x 10 ^11m and the distance between earth and moon is 1492.16 x 10^8 m.during solar eclipse moon comes in between earth and sun .at that time what is the distance between moon and sun.
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Answered by
33
simply subract distance to the sun from distance to the moon
ie. 1.496 x 10^11-1492.16 x 10^8
10^10 x (14.96-14.9216)
0.0384 x 10^10 ~ 3.84 x 10^8
ie. 1.496 x 10^11-1492.16 x 10^8
10^10 x (14.96-14.9216)
0.0384 x 10^10 ~ 3.84 x 10^8
rajesh8298:
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Diameter of a wire on a computer chip is 0.000003m and thickness of a piece of paper is 0.0016cm.find the sum of diameter of 1000 computer chips and thickness of 20 pieces of paper. Plss solve expert , hope u
Answered by
34
ki$ = Sun
@ = Earth
© = Moon
$----------------------------------@
(1.496×10^11)
@---------------------------------©
(1.492×10^8)
$---------------------©--1.492×10^8--@
|________1.496×10^11_________|
Distance between Sun and moon at solar eclipse.
= 1.496×10^11-1492.16×10^8
= 1496×10^8-1492.16×10^8
= 10^8(1496-1492.16)
= 10^8(3.84)
≈ 3.84×10^8 metres.
Plz Mark It As Brainliest Answer.
@ = Earth
© = Moon
$----------------------------------@
(1.496×10^11)
@---------------------------------©
(1.492×10^8)
$---------------------©--1.492×10^8--@
|________1.496×10^11_________|
Distance between Sun and moon at solar eclipse.
= 1.496×10^11-1492.16×10^8
= 1496×10^8-1492.16×10^8
= 10^8(1496-1492.16)
= 10^8(3.84)
≈ 3.84×10^8 metres.
Plz Mark It As Brainliest Answer.
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Diameter of a wire on a computer chip is 0.000003m and thickness of a piece of paper is 0.0016cm.find the sum of diameter of 1000 computer chips and thickness of 20 pieces of paper.
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Diameter of a wire on a computer chip is 0.000003m and thickness of a piece of paper is 0.0016cm.find the sum of diameter of 1000 computer chips and thickness of 20 pieces of paper.
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