Physics, asked by nocramming734, 1 year ago

The distance between the frist and third crest of the wave is 4.5m then it's wavelength is?

Answers

Answered by SerenaBochenek
4

The answer to the question is 2.25 m.

CALCULATION:

The distance between two successive crests or troughs is called wavelength of the wave.

As per the question, the distance between the first and third crest is 4.5 m.

We are asked to calculate the wavelength of the wave.

Let the wavelength of the wave is \lambda.

As we are considering first and third crests, then the distance between first and third crest will correspond to twice of wavelength.

Hence, the distance between first and third crest is 2\lambda

It is given that 2\lambda=4.5\ m

                      ⇒  \lambda=\frac{4.5}{2}\ m

                        =\ 2.25\ m

Hence, the wavelength of the wave is 2.25 m.

Answered by topanswers
3

Given:

The distance between the first and third crest of the wave = 4.5 m

To find:

Wavelength.

Solution:

To find the wavelength,

Given the distance between successive crests,

2λ = distance between successive crests

Where,

λ is the wavelength of the wave.

Substituting,

We get,

2λ = 4.5

λ = 4.5/2

λ = 2.25 m

Hence, the wavelength is 2.25 m.

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