Question

the distance between the lines 4x+3y=11 and 8x+6y=15

Answer 1

through thies eqn will can easly understand that they are paralle eqn
so, for second eqn 8x+6y=15 divided it by 2
we get, 4x+3y=15/2 which shows parallel eqn
Than we have to use this formula
= | D2-D1/whole root Asqu + Bsqu |
by this , | 15/2-11/ root 4squ+3squ |
AnD your answer is,
=7/2 upon root 25
,which gives 7/10 your final answer.. :)

Answer 2

Answer:

= $\frac{7}{10}$

Step-by-step explanation:

Given lines are 4x + 3y = 11 and 4x + 3y = $\frac{15}{2}$

Distane between two parallel lines

             |c₁ - c₂ / √a² + b²|

= | 11 - $\frac{15}{2}$ / √16 + 9 |

= | 7 / 2 × 5 |

= $\frac{7}{10}$

Good luck !!