the distance between the object and its inverted image formed by a concave mirror is 15cm if the magnification produced by the mirror is-2 determine the object distance image distance and focal length
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Answered by
11
-v + u = 15cm => u=15+v
m= -v/u
-2= -v/15+v => -2(15+v)=-v
-30+(-2v)= -v -30=v
therefore the image distance is -30cm
m=-v/u
-2=-(-30)/u =>-2u=30
u=-15cm
therefore the object distance is -15cm
1/f= 1/v +1/u
=-1/30 + -1/15
=-1/30 -2/30
=-3/30
1/f = -1/10
f=-10cm
therefore the focal length of the mirror is -10cm
m= -v/u
-2= -v/15+v => -2(15+v)=-v
-30+(-2v)= -v -30=v
therefore the image distance is -30cm
m=-v/u
-2=-(-30)/u =>-2u=30
u=-15cm
therefore the object distance is -15cm
1/f= 1/v +1/u
=-1/30 + -1/15
=-1/30 -2/30
=-3/30
1/f = -1/10
f=-10cm
therefore the focal length of the mirror is -10cm
Answered by
0
Answer: u=-15cm
v=-30cm
f=-10cm
Explanation:
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