The distance between the parallel planes
2x – 3y + 6z + 1 = 0 and
4x – 6y + 12z - 5 = 0) is
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Answer:
2/1 units
Step-by-step explanation:
2x−3y+6z+1=0
4x−6y+12z−5=0
implise2x−3y+6y− 5/2=0
Distance between the given planes
= (d1-d2)/√a²+b²+c²
=(1+5/2)/√4+9+36
= 2/1 units
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