Question

the distance between the plates of a parallel plate capacitor is 3mm and the potential difference applied is 3*10^5 V. if an electron travels from one plate to another, the change in its potential energy is (answer in eV)

Answer 1

the distance between the plates of a parallel plate capacitor is 3mm and the potential difference applied is 3*10^5 V. if an electron travels from one plate to another, the change in its potential energy is ...

solution : potential difference between the plates , ∆V = 3 × 10^5 Volts.

an electron transfer from one plate to another. Let us consider that charge on electron is e. [ well, e = 1.6 × 10^-19C but we have to find potential energy in eV so, just put charge of electron is e.]

now, potential energy = charge transfer from one plate to another × potential difference between plates

= e × 3 × 10^5 V

= 3 × 10^5 eV

hence, answer should be 3 × 10^5 eV

Answer 2

Answer:

answer is 3×10^5 eV

Explanation:

see attached image for better understanding..

hope it helps..

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