Math, asked by ezenwamartins, 8 months ago

The distance between the point (1,2) and (x,-1) is 5units. Find the possible value of x

Answers

Answered by asmithawagmare

0

Step-by-step explanation:

1-x/2+1=5. ( x1-x2/y1-y2)

1-x/3=5

1-x=5×3

1-x=15

x=-(15-1)

x=14

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