the distance between the point (4,3) and the origin is
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Answered by
6
Answer:
Origin (0,0)
Point A (4,3)
Distance formula = \sqrt{( x^{2} +y^{2})}
Distance = \sqrt{3^2 + 4^2}
= \sqrt{9+16}
= \sqrt{25}
= 5
Answered by
5
⏩P(4,3)
The given point is P (4, 3).
Distance of point P from x-axis is 3 units.
Distance of point P from y-axis is 4 units.
Distance of point P from origin = OP, where O is the origin.
From P draw line A perpendicular to x-axis.
You can observe that OAP is a right angled triangle with OA = 4 units, AP = 3 units.
So, using Pythagoras theorem,
OP2 = 42 + 32 = 25 => OP = 5 units
Hence, the distance of point P from origin is 5 units.
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