Question

The distance between the point P(1,4) and Q (4,0) is

Answer 1

Answer:

5

Step-by-step explanation:

PQ=

$\sqrt{(x2 - x1) + (y2 - y1)}$

$\sqrt{(4 - 1)^{2} } +( 0 - 4)^{2}$

$\sqrt{(3)^{2} } + ( - 4) {}^{2}$

$\sqrt{9 + 16}$

$\sqrt{25}$

$5$

Answer 2

Answer

5

Step-by-step explanation:

P=(1,4). Q=(4,0)

by using distance formula =√(x2-x1)²+(y2-y1)²

=√(4-1)²+(0-4)²

=√3²+(-4)²

=√9+16

=√25

=5