Question

the distance between the point p (-3, 7) and Q(5,4
)​

Answer 1

Answer:

Distance 1/10

Step-by-step explanation:

given points are p(-3,7)   Q(5,4)

x1=-3          y1=7

x2=5          y2=4

distance =(y2-y1)/(x2-x1)

              =(4-5)/(7-(-3))

              = -1/(7+3)

              =-1/10

so the distance is  1/10

Hope this answer is helpful to you....

Answer 2

Answer:

HOPE THIS WAS HELPFUL

PLS MARK BRAINLIEST

Step-by-step explanation:

Given P(−5,−4),Q(3,−7)

PQ=  

(−5−3)  

2

+(−4+7)  

2

 

​  

=  

64+9

​  

=  

73

​  

 

Distance between P and Q is  

73

​  

 units