Question

The distance between the points (-3,0) and (1,0) is

Answer 1

Answer:

$\sqrt{(x2 - x1)^2 (y2 - y1)^ 2$

$\sqrt{{(1 - ( - 3)}^{2} } + {(0 - 0)}^{2}$

$\sqrt{ {(4)}^{2} } + \sqrt{ {0}^{2} }$

$\sqrt{16}$

=4

Answer 2

Answer:

Question: The distance between the points (-3,0) and (1,0) is

Difficulty : Easy

Answer:

The points are : A(-3,0) and B(1,0)     (∵Let)

By distance formula,

$AB = \sqrt{(x2-x1)^{2} +(y2-y1)^{2} } \\AB= \sqrt{(1-(-3))^{2} +(0-0)^{2} }\\AB = \sqrt{4^{2} } \\AB = 4$

Hope it helps you.

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