Question

The distance between the points (3,1) and (0,x) is 5 units find x

Answer 1

x is equal to -3 or 5

Answer 2

Answer:

The value of x is either 5 or -3.

Step-by-step explanation:

The distance formula is

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The end points are P(3,1) and Q(0,x). It is given that the length of PQ is 5 units.

$PQ=\sqrt{(0-3)^2+(x-1)^2}$

$5=\sqrt{(-3)^2+(x-1)^2}$

Squaring both the sides.

$25=9+(x-1)^2}$

$16=(x-1)^2}$

Take square root both the sides.

$\pm \sqrt{16}=x-1$

$\pm 4=x-1$

$\pm 4+1=x$

$x=5,-3$

The value of x is either 5 or -3.