The distance between the real enlarged image and the object placed in front of a concave mirror is 60cm.If the focal length of the mirror is 40cm find the position of the object and the image.
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we have v-u=60cm
but using sign convention we get
u=60+v
and using mirror formula
-1/40=1/v+1/60+v
on solving it we get an quadratic equation
v²+140v+2400=o
on solving it we get
v=-120cm
and hence we get
u=-60cm
but using sign convention we get
u=60+v
and using mirror formula
-1/40=1/v+1/60+v
on solving it we get an quadratic equation
v²+140v+2400=o
on solving it we get
v=-120cm
and hence we get
u=-60cm
does it is correct
hope so!
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