Question

The distance between the school and the house of a student house is 1 km 875 everyday she walks both way find the total distance covered by her sin day

Answer 1

Answer:

3.750

Step-by-step explanation:

 1.875

+1.875

______

 3.750

______

Answer 2

$\blue{ \underline{\underline{\huge\mathfrak\pink{Answer}}}}$

$\mathtt \blue{Distance \: between \: school \: and \: house }$

$\implies \mathtt{1km \: 875m} \\ \implies \mathtt{1km \ + 875m} \\ \orange{\boxed{\implies \mathtt{1km + 1000m}}} \\ \implies \mathtt{1000 + 875m} \\ \blue{\fbox{\boxed{\implies \mathtt{1875m}}}}$

$\underline{\underline\mathtt\red{ Given \: that}}$

$\mathtt \green{She \: walks \: both \: ways}$

$\mathtt \orange{So, \: She \: walks \: the \: distance \: twice \: in \: 1 \: day}$

$\mathtt \purple{Distance \: coverd \: in \: a \: day = 1872 \times 2}$

$\mathtt \pink{Distance \: coverd \: in \: six \: day = 1872 \times 2 \times 6}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathtt \green{= 1875 \times 12}$

$\mathtt \red{Total \: distance \: coverd \: in \: \: six \: days}$

$\red{\fbox{\boxed{\mathtt\red{ = 22500}}}}$

${\green{\fbox { \purple {\fbox {\blue {\boxed{\mathtt \pink{22500 = 22km 500m}}}}}}}}$