Question

the distance between the tops of two trees 20m & 28m high is 17m. the horizontal distance between the tree is what ?​

Answer 1

Answer:

Let there are two trees AB and CE whose heights are 20 m and 28 m respectively. Hence, the distance between two trees is 15 m.

Answer 2

Answer:

Let the small tree top be AB and the tall tree top be PQ .

.: The distance between the two tree tops is AP=17m.

Draw a perpendicular from A meeting PQ at S such that AB=QS=20m.

Now, PS=PQ-SQ

=28-20

PS=8m.

APS is a right angled triangled because AS is perpendicular to PQ.

.: AP^2=PS^2+AS^2

(17)^2=(8)^2+AS^2

289=64+AS^2

289-64=AS^2

225=AS^2

AS=15m.

.:The horizontal distance between the two tree tops is 15 m.

Step-by-step explanation:

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