Question

If the management of NCC TRAINING
Camp likes to allot space for some more
sports, how much area is available to

them?

(a) 85, 536 m2

(b) 95, 800 m2

(c) 60, 040 m2

(d) 69,336 m2​

Answer 1

Given : (complete Question is )

The areas allotted for a hockey court and a shooting range of NCC TRAINING CAMP

The shapes of the hockey court and the shooting range are square and triangle respectively. Both of the courts have a common vertex that coincide with the centre of circular camp. The construction of the shooting range is such that the angle to centre is 90°. The radius of the circular camp is 180 metres.  

To Find :

1) What is the area allotted to shooting  range ?

(a) 12, 600 m²  (b) 22, 000 m²  (c) 16,200 m²  (d) 16, 880 m²

2) What is the area allotted to hockey court ?

(a) 12, 600 m²  (b) 22, 000 m²  (c) 20, 000 m²   (d) 16, 200 m²

3) What is the area of training camp.

(a) 101736 m²  (b) 32400 m²  (c) 16200 m²   (d) 20000 m²

4) If the management of NCC TRAINING  Camp likes to allot space for some more  sports, how much area is available to  them?

(a) 85, 536 m² (b) 95, 800 m²  (c) 60, 040 m² (d) 69,336 m²

Solution  :

OA = OB = Radius = 180 m

angle = 90°

Area of shooting  range = (1/2) * 180 * 180 =  16200 m²

OD = Radius = 180 m

OE = 180/√2  = 90√2  m  

Area of Hockey court = (90√2)² = 16200 m²

area of training camp. = π(180)² = 3.14(180)² =    1,01,736 m²

area is available =  1,01,736 -  16200 -  16200  = 69,336 m²

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