THE DISTANCE BETWEEN TWO CITIES A AND B IS 425 KM . IF A CAR LEAVE A AT 2 P.M.AND REACH B AT 10.30. PM WHAT IS THE SPEED OF THE CAR?
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Answered by
8
Distance = 425 km
Time taken = 10.30 pm - 2 pm
= 8 hours 30 minutes = 510 minutes
Speed = D/T = 425/510
Time taken = 10.30 pm - 2 pm
= 8 hours 30 minutes = 510 minutes
Speed = D/T = 425/510
tisrisu:
sorry but its wrong
Answered by
19
We know that Speed = Distance / Time
Distance = 425 km
Time = 10.5 - 2 = 8.5 hours
Speed of car = 425 / 8.5
Speed of car = 50
So, the speed of car is 50 km / Hour
Distance = 425 km
Time = 10.5 - 2 = 8.5 hours
Speed of car = 425 / 8.5
Speed of car = 50
So, the speed of car is 50 km / Hour
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