Question

the distance between two points (0,0)and (x,3)is 5 find x​

Answer 1

Step-by-step explanation:

Distance between (0,0) and (x,3) is 5.

$\sqrt{ {x}^{2} + 9} = 5 = > {x}^{2} + 9 = 25 = >$

${x}^{2} = 25 - 9 = 16 = > {x}^{2} = 16 = >$

${x}^{2} - 16 = 0 = > (x - 4)(x + 4) = 0$

$= > (x + 4) = 0 \: or \: (x - 4) = 0 = >$

$x = - 4 \: or \: 4$

Hope it helps you.

Answer 2

Answer:

The distance between two points (0,0)and (x,3) is 5 then the value of  x​=4.

Step-by-step explanation:

The distance between (x1,y1) and (x2,y2) is given by $\sqrt{(x_{2}-x_{1)^{2} +(y_{2}-y_{1})^{2} } }$

Given points (0,0) and (x,3)

where x1=0, y1=0 x2=x ,y2=3

$\sqrt{(x-0)^{2} +(3-0)^{2} } }$ = 5

$\sqrt{ x^{2}+3^{2}$ = 5

x² + 9 = 5²

x² = 25 - 9

x² = 16

x = √16

x = 4

The distance between two points (0,0)and (x,3) is 5 then the value of      x​=4.