the distance between two points P(1,0) and Q( 2, cotA) is
tan A
sec A
cot A
cosec A
pls fast
Answers
Answer:
Correct option is
B
10
Distance =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
[5−(−1)]
2
+[−7−1]
2
=
6
2
+8
2
=
100
=10 units

Solution :-
we know that, according to distance formula ,
- Distance between P(a,b) and Q(c,d) is equal to = √[(a - c)² + (b - d)²]
so, using distance formula we get,
→ PQ = √[(1 - 2)² + (0 - cot A)²]
→ PQ = √{(-1)² + (-cot A)²}
→ PQ = √(1 + cot²A)
using 1 + cot²A = cosec²A we get,
→ PQ = √(cosec ²A)
→ PQ = cosec A (Ans.)
Hence, the distance between two points P(1,0) and Q( 2, cotA) is cosec A .
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