Question

the distance between two points P(1,0) and Q( 2, cotA) is

tan A

sec A

cot A

cosec A

pls fast

Answer 1

Answer:

Correct option is

B

10

Distance =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

=

[5−(−1)]

2

+[−7−1]

2

=

6

2

+8

2

=

100

=10 units

Answer 2

Solution :-

we know that, according to distance formula ,

• Distance between P(a,b) and Q(c,d) is equal to = √[(a - c)² + (b - d)²]

so, using distance formula we get,

→ PQ = √[(1 - 2)² + (0 - cot A)²]

→ PQ = √{(-1)² + (-cot A)²}

→ PQ = √(1 + cot²A)

using 1 + cot²A = cosec²A we get,

→ PQ = √(cosec ²A)

→ PQ = cosec A (Ans.)

Hence, the distance between two points P(1,0) and Q( 2, cotA) is cosec A .

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