Question

the distance between two protons such that electrical repulsive force between them equal to the weight of either​

Answer 1

Weight of proton=1.673×10^-27 kgf,

The electric charge of proton q=1.602×10^-19c

Assuming their distance be x for their repulsive force to be equal to individual weight⇒kq²/x²= 1.673×10^-19×9.81

⇒x²=9×10^ 9×1.602²×10^-38/(1.673×10^-27)

⇒x²=9×{1.602²/1.673}×10^(8+27-38)

=13.806×10^-3m or 13.806mm........................

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