The distance between two stations is 400 km. A train goes from one station to the other with a speed of 50 km/hr and returns with a speed of 40 km/hr. What the average speed of the train during the journey?
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Answered by
0
Answer:
Net displacement of the train in coming back to the first station is zero i.e. S=0 .
Average velocity V
avg
=
t
S
=0
Average speed of the train when in moving equal distances is given by ∣V∣
avg
=
v
1
+v
2
2v
1
v
2
⟹ ∣V∣
avg
=
40+60
2×40×60
=48 km/h
Answered by
1
Explanation:
2×40×60/40+60= 48km/h
by avg v formula
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