Question

the distance between two stations is 432 km . a train takes 6 hours to cover his distance . calculate the speed of the train in km/hr and m/s.​

Answer 1

$\huge\rm\underline{Answer:-}$

$\tt\underline{Given:-}$

• Distance $(s)$ between the two stations = $\bf{432 \ km}$
• Time it takes $(t)$ = $\bf{6 \ hr.}$

$\tt\underline{To \ Find:-}$

Speed in $km {h}^{-1}$ and $m {s}^{-1}$.

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We know,

$v = \frac{s}{t}$

$\therefore v = \frac{432 \ km}{6 \ hr}$

$\implies v = \frac{\cancel{432 \ km}}{\cancel{6 \ hr}}$

(Common = 6)

$\implies v = \frac{72 \ km}{hr}$

$\boxed{\sf{ \implies v = 72 \ km \ {h}^{-1}}}$

Now,

Converting them into $m {s}^{-1}$.

We know, to convert km h⁻¹ to m s⁻¹, we have to multiply the speed with 5/18.

$\therefore 72 \times \frac{5}{18} \ m \ {s}^{-1}$

$= 4 \times 5 \ m \ {s}^{-1}$

$\boxed{\sf{= 20 \ m \ {s}^{-1}}}$