the distance between two two stations A and B is 230 km.Two motorcyclist starts simultaneously from A and B in the opposite direction and the distance between them after 3 hours is 20 km.if the speed of one motor cyclist is less than the other by 10 km/he,find the speed of each motorcyclist.
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Answered by
83
Let speed of bike A is X.
Than speed of bike B will be X+10.
Total distance traveled by both bikes is 210
Bicoz difference is only 20km.
(X+10)3+3X=210.
BY equating it
X=30.
That's why speed of A=30
B=40.
Than speed of bike B will be X+10.
Total distance traveled by both bikes is 210
Bicoz difference is only 20km.
(X+10)3+3X=210.
BY equating it
X=30.
That's why speed of A=30
B=40.
Answered by
6
Answer:
Let speed of bike A is X.
Than speed of bike B will be X+10.
Total distance traveled by both bikes is 210
Bicoz difference is only 20km.
(X+10)3+3X=210.
BY equating it
X=30.
That's why speed of A=30
B=40.
Step-by-step explanation:
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