The distance between v and u is 15 cm and magnification is -2 in a concave mirror calculate v and u
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(a) Concave mirror
(b) u = - 15 cm
v = - 90 cm
Linear magnification m = -v/u = - (-90)/(-15) = - 6
(c) Distance between object and its image = 90 - 15 = 75 cm
(d) 1/f = 1/v + 1/u = 1/(-90) + 1/(-15) = -7/90
f = -90/7 ≅ 12.9 cm
So the object is placed between F and C.
An inverted magnified real image is formed beyond C
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