Question

The distance covered by a particle in time t is given by x=a+bt+ct^2+dt^3 . find the dimensions of a,b,c,d

Answer 1

Explanation:

X is distance = [L]

dimensions of quantities in LHS should be same as on RHS

therefote at RHS all quantities should be distance too.

hence a = [ L ]

bt = [ L ]

thus , b = [ L T^(-1) ]

,. C = [ L T^(-2) ]

d = [ L T^(-3) ]

Answer 2

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