Question

the distance covered by the falling body from rest in the first second and third seconds are in the ratio of​

Answer 1

by free fall equation

distance cover in 1th sec=s1=1/2×g×1^2

and in 3rd sec=s2=1/2×g×3^2

by ratio

s1:s2=(1/2×g)/(1/2×g×9)

=1:9

hence ,ratio will 1:9