Question

The distance covered by the mass in 5 seconds​

Answer 1

Given :-

✰ F = 2N, m=0.5kg, u=0 & t=5sec

Solution :-

(i) At first, we need to find the value of( a) acceleration.

Hence, a = F/m = 2/0.5 = 4m/s^2

As we know, s = ut + 1/2 at^2

= 0+1/2 *4*(5)^2

=50 m

(ii) According to the question,

(ii) According to the question,Velocity acquired at the end of 5sec is, v

= u+at

= 0+4*5

=20 m/s

Hence, distance moved in next 5sec is

= v*t

= 20*5

= 100m

Here , remember that the velocity is uniformed.