Question

The distance D from the fulcrum of a seesaw varies inversely as the weight of the person W. Dale who weighs 120 pounds, sits 4 feet from the fulcrum. Dave, who weighs 80 pounds, sits 3 ft from the fulcrum. What should Dave do to balance Dale’s weight?

A. Dave should sit 5 ft from the fulcrum.

B. Dave should sit 6 ft from Dale’s position.

C. Dave should sit 3 ft farther from his present position.

D. Dave should sit 6 ft farther from his present position.​

Answer 1

Dave do to balance Dale's weight is

(C.) Dave should sit 3 ft farther from his present position.

Step -by step- explanation:

Given, Dale who weighs 120 pounds,sits 4 feet from the fulcrum.Dave,who weighs 80 pounds,sits 3 feet from the fulcrum.

Find: what should Dave do to balance Dale's weight?

solution:

According to the equation:

let, $y=a/x$

⇒$4=a/120$

⇒$a=480$

⇒$y=480/x$

when , $x=80,y=480/80=6.$

So, Dave should sit 6 feet from the fulcrum or 3 feet farther from his present position or 10 feet from Dale's position.