Math, asked by sukrit9931, 1 year ago

The distance from a to b is 60 km. Partha and narayan start from a at the same time and move towards b. Partha takes four hours more than narayan to reach b. Moreover, partha reaches the mid-point of a and b two hours before narayan reaches b. The speed of partha, in km per hour, is

Answers

Answered by somi173
4

Answer:                

                      ⇒ Speed of Partha = 5km/hr

Given that

Total distance between a & b = 60 km

Let the time taken by Narayan to cover 60 km = x hours

Then

The time taken by Partha to cover 60 km = x+4 hours   ......... (i)

⇒ Distance of mid-point of a & b from the point a = 30 km

Partha reaches the mid-point in time = x-2 hours

⇒  Partha covers a distance of 30 km in time = x-2 hours

⇒  Partha covers a distance of 60 km in time = x-2  +  x-2  = 2x-4 hours ..(ii)

From (i) and (ii) , we have

2x - 4 = x + 4

2x - x = 4 + 4

 x = 8 hours

Thus time taken by Partha to cover 60 km = x+4 = 8 + 4 = 12 hours

Partha covers distance in 12 hours = 60 km

Partha covers distance in 1 hour = 60/12 km/hr = 5km/hr

⇒   Partha covers distance in 1 hour =  5km/hr


Answered by k28
0

Answer:

Speed of Partha is 5km/hr

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