Physics, asked by pulastwinni, 5 months ago

The distance moved by car Q during the time interval in which they cross each other is
(1) 60 m
(2) 15 m
(3) 330 m
(4) 54 m

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Answers

Answered by Rizakhan678540
2

Answer:

Total distance covered :-

 = 90 + 10 \\  = 100m \\

Relative velocity :-

 = 15 + 10 \\  = 25m.s \\

Time taken :-

 =  \frac{100}{25}  \\  = 45 \\

distance travelled by Q :-

 = 15 \times 4 \\  = 60

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Answered by 22112005VishnuR
0

Answer:

60m

Explanation

Given that, speed of car P and Q is vp=10m/s,vq=15m/s

Length of each car =5m

and separation between the cars=90m

Total distance covered(d)=90+5+5=100m

Relative velocity(v)=10+15=25m/s

Time taken(t)=dv=10025=4s

Distance traveled by Q,(dp)=vp×t=15×4=60m

Hence, the distance moved by the car Q during the time interval in which they completely cross each other is60m

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