the distance of B (3,8) from the origin is
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Answer:
The distance between A(1,2) and B(3,8) is double of the distance of C(3,-1) from the origin
We know that , the distance b/w two points is given by
Thus , the distance between A(1,2) and
B(3,8) will be
AB = √{(3 - 1)² + (8 - 2)²}
AB = √{4 + 36}
AB = √40
AB = 2√10 units
Now , the distance between C(3,-1)
from the origin or D(0,0) will be
CD = √{(0 - 3)² + (0 + 1)²}
CD = √{9 + 1}
CD = √10 units
It is observed that ,
CD = 2AB
Hence proved
Step-by-step explanation:
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