The distance of P from Q is 7 km an aeroplane flew from P to Q against the wind and then comes back in 22 minutes.If it's speed was decreased by 12.5%flying against the wind and increased by 5% when flying with the wind, how long would the flight have taken had there been no wind ?
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Answer:0.38 hour
Step-by-step explanation:
v(aeroplane)-v(wind)=v*(100-12.5%)
v(aeroplane)+v(wind)=v*(100+5%)
22/60=11/30 (h)
7/(11/30) =210/11 (km/h)
v=210/11 (km/h)
=> v(aeroplane) = 18.37 km/h. v(wind)=1.67 km/h
=>t(without wind) =7/18.87=0.38 (h)
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