Question

The distance of point ( -3, 4) from origin is

Answer 1

Distance from origin
So points (0,0)= x1,x2
And (-3,4)= y1,y2
Now distance = √(x2-x1)sq +(y2-y1)sq

= √ (4-0)sq +(-3-0)sq
=√16+ 9
= √25
= 5 units ans

Answer 2

Answer:

5 units

Step-by-step explanation:

Point of origin = $(x_1,y_1)=(0,0)$

Another point  = $(x_2,y_2)=(-3,4)$

So, to find the distance between the given points we will use distance formula :

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the given values .

$d=\sqrt{(-3-0)^2+(4-0)^2}$

$d=\sqrt{(-3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d=5$

Hence the distance of point ( -3, 4) from origin is 5 units.