Question

the distance of point p ( -3,-4) from x axis is​

Answer 1

Answer:

Hello ❤️

As we know on x axis y co-ordinate is 0

So the points are (x, 0)

Now,

$d = \sqrt{(x - ( - 3)) 2 + (0 - ( - 4)2)} \\ d = \sqrt{ {(x + 3)}^{2} + {4}^{2} } \\ d = \sqrt{ {x}^{2} + 9 + 6x + 16 } \\ d = \sqrt{ {x}^{2} + 6x + 25}$

Answer 2

Answer:

the coordinates of x axis are (x,0)

(-3-x)^2 = (0+4)^2

x^2 + 9 + 6x = 16

x^2 + 6x - 7 =0

u can factorize it