Question

The distance of the co-ordinate P(x, y) and origin is 10 units then the co-ordinate of point P is​

Answer 1

Answer:

Let O be the origin and Q be the foot of the perpendicular dropped from P onto the x axis.

So ΔOPQ is right-angled at Q.

By definition of coordinates:

OQ=x coordinate of P= distance of P from y axis =∣x∣

Similarly, QP=∣y∣.

Thus, by using Pythagoras theorem on ΔOPQ, we get OP=

< /p > < p > OQ2+QP2=x2+y2 </p><p>OQ2+QP2=x2+y2

Thus the distance of the point P(x,y) from the origin O(0,0) is

x < /p > < p > 2 < /p > < p > +y < /p > < p > 2 < /p > < p >x</p><p>2</p><p>+y</p><p>2</p><p>