Math, asked by anushikapundir, 7 months ago

the distance of the point P(4 ,-3) from the origin is ?

Answers

Answered by RishitaTanmai
0

Step-by-step explanation:

p(X,y) =√[x^2+y^2]

=(4)^2+(-3)^2

=16+9=25

Answered by Shivam1027
0

Answer:

The point P(4,-3) will form a triangle on the cartesian plane.

Base = 4 units

Perpendicular = 3 units

Distance from the origin (hypotenuse) = √(B^2+P^2)

= √(4^2+3^2)

= √(16+9)

= √25

= 5 units

Ans. The distance of the point P(4,-3) from the origin is 5 units.

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