the distance of the point P(4 ,-3) from the origin is ?
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Answered by
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Step-by-step explanation:
p(X,y) =√[x^2+y^2]
=(4)^2+(-3)^2
=16+9=25
Answered by
0
Answer:
The point P(4,-3) will form a triangle on the cartesian plane.
Base = 4 units
Perpendicular = 3 units
Distance from the origin (hypotenuse) = √(B^2+P^2)
= √(4^2+3^2)
= √(16+9)
= √25
= 5 units
Ans. The distance of the point P(4,-3) from the origin is 5 units.
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