Question

the distance of the points(3,-4) from origin is​

Answer 1

Answer:

5 units

Step-by-step explanation:

Distance from origin is given by the formula= $\sqrt{x^{2}+y^{2} }$

Hence, here, x=3 and y=-4

Distance= $\sqrt{3^{2} +-4^{2} }$

               = $\sqrt{9+16}$

               =$\sqrt{25}$

                = 5 units.

Hence the distance of point (3, -4) from the origin is 5 units.

Answer 2

Answer:

origin is (0,0) and pt is (3,-4)

so applying distance formula.......

\sqrt{(x2 - x1) { } ^{2} + )y2 - y1)  {}^{2} }  

\sqrt{(3 - 0 {})^{2}  + ( - 4 - 0) {}^{2} }  

\sqrt{9 + 16}  

\sqrt{25}  

= ±5

but distance cant be negative....

so rejecting negatuve value.....

hence answer is.....

5 units......

hope it helps....

Step-by-step explanation: