The distance(S)–time(t) graph of an object of mass 2kg moving along a straight is as shown above. The net work done on the object in the first four seconds is
(1). 16J (2). ZERO
(3). 32J (4). 8J
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Answer:
ZERO
Explanation:
because velocity is constant hence acceleration is zero thus force is zero. hence work done is zero.
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