Question

The distance-time graph of two trains is given below. The trains start simultaneously in the same direction. (a)How much ahead of A is B when the motion starts? (b)What is the speed of B ? (c)When and where will A catch B? (d)What is the difference between speeds of A and B? (e)Is the speed of both the trains uniform or non-uniform? Justify your answer C.
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Answer 1

(a) Train B is 10km ahead of Train A

(b) speed of train B = Q-R/P-R

$= > \frac{150 - 100}{2 - 0} = \frac{50}{2} = 25kmh$

(c) Train A will catch the Train B at the point Q at a distance of 150km

(d) Speed of Train A = Q-S/O-S

$\frac{150 - 0}{2 - 0} = \frac{150}{2} = 75kmh$

(e) As they move in same direction with same speed and distance so the speed of both the trains will be uniform