Question

The distance traveled s by an accelerated particle of mass m is given by the following s=6t-3t^2.velociyu of the particle after 2 sec

Answer 1

s = 6t-3t²

We know, Differentiation of displacement gives velocity,

so,

v = ds/dt = d6t-3t²/dt

=>d6t/dt + d-3t²/dt

=>6t¹-¹ -2×3t²-¹

=>6-6t

Velocity at t = 2 seconds

=>6-6t = 6-6×2 = 6-12 = -6m/s

So, the velocity if the particle after 2seconds = -6m/s

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