Question

Three person can complete half of the work in 8 days .If one of them discontinues working how many days would you take to do remaining half

Answer 1

Let's assume total amount of work to be done is X.

Therefore 3 workers in 8 days can do ‘X/2’

1 worker in 1 day can do ‘X/48’

Now since one worker leaves after 8 days amount of work he did is ‘X/6’ [ X/48 × 8 ]

Let other two work for ‘t’ days,

X/6 + X/48 ×t + X/48 ×t = X

Solving this we get t = 20 days.

Hope this helps...☺