Question

The distance travelled by a body in the 4" second is twice the distance travelled in the 2nd second. If the acceleration of the body is 3 ms2, then its initial velocity is 2) 5/2 ms- 3) 7/2 ms 4) 9/2 ms 3 1) 3/2 ms-​

Answer 1

Explanation:

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distance Travelled by an object in 4th sec is twice the distance travelled by it in 2nd second. If the acceleration of the object 3m s

−2

n is calculate (i) its initial velocity (ii) the distance travelled in 7th second.

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Solution

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Let s

n

be the distance travelled in n_{th} sec

s

n

=u+

2

a

(2n−1)

s

4

=2s

2

u+3.5a=2u+3a

u−0.5a=0

u=0.5a

u=1.5

using:s

n

=u+

2

a

(2n−1)

s

7

=1.5+

2

3

(2×7−1)

s

7

=21m