Question

. The distance travelled by a body is found to be directly
proportional to the square of time. Is the body moving
with uniform velocity or with uniform acceleration ?
If the distance travelled be directly proportional to
time, then ?​

Answer 1

Answer:

Heya mate,

With uniform acceleration, with uniform velocity.

Hope it helps you..

Answer 2

Answer:

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dt

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2kt

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2ktWe see that velocity is not constant with changing with time.

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2ktWe see that velocity is not constant with changing with time.We once against differentiate and get a (acceleration) = dv/dx

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2ktWe see that velocity is not constant with changing with time.We once against differentiate and get a (acceleration) = dv/dxa = dv/dx = 2k

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2ktWe see that velocity is not constant with changing with time.We once against differentiate and get a (acceleration) = dv/dxa = dv/dx = 2kWe see that a does not depend on t but a constant (2k)

Given x = kt² (where x: distance travelled, t: time and k: proportionality constant)On differentiating above, we get v (velocity) = dx/dtv = = dx/dt = 2ktWe see that velocity is not constant with changing with time.We once against differentiate and get a (acceleration) = dv/dxa = dv/dx = 2kWe see that a does not depend on t but a constant (2k)We conclude that the body is moving with constant acceleration and not with constant velocity.