Question

The distance travelled by a stone dropped from a height 200 metres in 3
seconds is (when g = 10 m/sec)
(A) 90 m (b) 45 m (C) 30 m
(D) None of these​

Answer 1

Answer:

diatance /s = 200 m and it is dropping from some height so the value of u =0 time = 3s g=10m/s^2

Explanation:

using h=ut+ 1/2×at^2

h = 0×3 + 1/2 × 10 × (3)^2

h= 0 + 1/2 × 10 × 9

h= 0 + 5 ×9

h= 45m

plz mark me as brainlist