Question

The distance travelled by an object along straight line x=180t+50t^2 find until velocity and final velocity at 4s and acceleration

Answer 1

Answer:

Initial velocity = 180 m/s

final velocity(at t = 4s) = 580 m/s

Acceleration = 100 m/s

Step by step explanations :

Given that,

The distance travelled by an object along straight line x = 180t + 50t²

velocity of the object = dx/dt

= 100t + 180

Initial velocity of the object = velocity

at t = 0

so,

Initial velocity = 100(0) + 180

= 180 m/s.

now,

final velocity at t = 4 s

= 100(4) + 180

= 400 + 180

= 580 m/s

so,

velocity of the object at t = 0 S

= 500 m/s

now,

Acceleration = dv/dt

= 100 m/s

so,

Initial velocity = 180 m/s

final velocity(at t = 4s) = 580 m/s

Acceleration = 100 m/s

Answer 2

Answer:

Initial velocity = 180 m/s

final velocity(at t = 4s) = 580 m/s

Acceleration = 100 m/s

Step by step explanations :

Given,

x = 180t + 50t²

velocity = dx/dt

= 100t + 180

Initial velocity of the object = velocity

at t = 0

so,

Initial velocity = 100(0) + 180

= 180 m/s.

now,

final velocity at t = 4 s

= 100(4) + 180

= 400 + 180

= 580 m/s

so,

velocity of the object at t = 0 S

= 500 m/s

now,

Acceleration = dv/dt

= 100 m/s

so,

Initial velocity = 180 m/s

final velocity(at t = 4s) = 580 m/s

Acceleration = 100 m/s