The distance travelled in a straight line motion is directly proportional to t1/2 where t is the time elapsed what is nature of motion
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s = k t^1/2
v = ds/dt = 1/2 k t^-1/2 = k / (2 sqrt(t))
So the velocity is proportinal to 1 / (square root of time). In other words it gets slower and slower, but never stops.
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v = ds/dt = 1/2 k t^-1/2 = k / (2 sqrt(t))
So the velocity is proportinal to 1 / (square root of time). In other words it gets slower and slower, but never stops.
HOPES THIS HELPS U !!!!!!!!!!!...............
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Answer:s = k t^1/2
v = ds/dt = 1/2 k t^-1/2 = k / (2 sqrt(t))
So the velocity is proportinal to 1 / (square root of time). In other words it gets slower and slower, but never stops
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